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16x^2+74x+9=0
a = 16; b = 74; c = +9;
Δ = b2-4ac
Δ = 742-4·16·9
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-70}{2*16}=\frac{-144}{32} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+70}{2*16}=\frac{-4}{32} =-1/8 $
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